You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Relation Between r and a

The edge leng...

Question

The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm.

$N_{A} = 6 \times 10^{2} 3$

457.8 pm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

216.5 pm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

789.5 pm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

257.8 pm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
216.5 pm

Watch the video that follows.

Suggest Corrections

Similar questions

Q. The edge length of unit cell of a metal having molecular weight 75 g/mol is 5

˚ A

which crystallises in cubic lattice. If the density is 2 g/cc then find the radius of a metal atom. (

N_{A} = 6 \times 10^{23}

). Give the answer in pm.

The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm.

$N_{A} = 6 \times 10^{2} 3$

Q. The edge length of unit cell of a metal having molecular weight

75

g/mol is

5 ˚ A

which crystallizes in cubic lattice. If the density is

2 g / c c

, then find the radius (in pm) of metal atom

(N_{A} = 6 \times 10^{23})

. Give answer in

p m

Q. The edge length of a unit cell of a metal having molecular weight

75

g/mol is

5 ˚ A

which crystallizes in a cubic lattice. If the density is

2

g cm

^{- 3}

, then find the radius (in pm) of the metal atom.

[Use

N_{A} = 6 \times 10^{23}

]

Q. The edge length of a unit cell of a metal that has a molecular weight 75 g/mol is

5 \circ A

. It crystallizes in a cubic lattice. If its density is 2 g/cc, then find the radius of metal atom in pm:

(N_{A} = 6 \times 10^{23}, \sqrt{2} = 1.41, \sqrt{3} = 1.73)

Join BYJU'S Learning Program

The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm. NA=6×1023

The correct option is B 216.5 pm Watch the video that follows.

The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm.

$N_{A} = 6 \times 10^{2} 3$

The correct option is B
216.5 pm

Watch the video that follows.