The edge length of a unit cell of chromium metal is $287 p m$ with $b c c$ arrangement. The atomic radius is of the order:

124.27 p m

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287 p m

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574 p m

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143.5 p m

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Solution

The correct option is A $124.27 p m$
For $b c c$ crystal,
$r = \frac{\sqrt{3}}{4} a$
$r = \frac{\sqrt{3}}{4} \times 287 r = 124.27 p m$ .
So, option A is correct answer.

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Chromium metal crystallises with a body-centred cubic lattice. The length of the unit cell edge is found to be 287 pm. Calculate the atomic radius. What would be the density of chromium in g/cc?

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The edge length of a unit cell of chromium metal is 287 pm with bcc arrangement. The atomic radius is of the order:

The correct option is A 124.27 pmFor bcc crystal,r=√34ar=√34×287r=124.27pm.So, option A is correct answer.

The edge length of a unit cell of chromium metal is $287 p m$ with $b c c$ arrangement. The atomic radius is of the order:

The correct option is A $124.27 p m$
For $b c c$ crystal,
$r = \frac{\sqrt{3}}{4} a$
$r = \frac{\sqrt{3}}{4} \times 287 r = 124.27 p m$ .
So, option A is correct answer.