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Electron Gain Enthalpy

The edge leng...

Question

The edge length of NaCl in the crystal is 552pm. If the ionic radius of $N a^{+}$ is 95pm, what is the ionic radius of $C l^{-}$ ?

550 p m

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181 p m

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371 p m

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276 p m

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Solution

The correct option is B $181 p m$
Edge length of $N a C l = 2 (r_{N a^{+}} + r_{C l^{-}})$

$552 = 2 (95 + r_{C l^{-}})$

$r_{C l^{-}} = 276 - 95$

$= 181 p m$

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