The correct option is B 2160cm3/sec
Let velocity v=5 cm/sec
(Increasing the rate/sec is called the velocity)
dadt=5....(i)
Where a is distance and t is time.
But if a is edge of a cube, then V=a3
Differentiating w.r.t. time t, so
dVdt=3a2dadt=3a2.5=15a2=15×(12)2
=2160cm3/sec (∵ edge a =12 cm)