The edge of a cube is measured using a vernier callipers. [9 divisions of the main scale is equal to 10 divisions of vernier scale and 1 main scale division is 1 mm]. The main scale division reading is 10 and 1 division of vernier scale was found to be coinciding with the main scale. The mass of the cube is 2.736 gm. Calculate the density in $g m / c m^{3}$ up to correct significant figures.

Open in App

Solution

Given, 9 MSD = 10 VSD
1 MSD = 1 mm
L.C. $= 1$ MSD-I VSD
$= 1$ mm- $\frac{9}{10}$ mm
$= \frac{1}{10}$ mm
Measured reading of edge $=$ MSR $+$ VSR $\times (L C)$
$= 10 + 1 \times \frac{1}{10} = 10.1 m m$
Volume of cube $= (10.1)^{3} = 1030.301 m m^{3}$
$= 1.030301 c m^{3}$
Density of the cube $= \frac{2.736}{1.030301} = 2.66 g m / c m^{3}$

Suggest Corrections

Similar questions

Q. The side of a cube is measured by Vernier callipers(

10

divisions of a Vernier scale coincide with

9

divisions of main scale, where

1

division of main scale is

1

mm). The main scale reads

10

mm and first division of Vernier scale coincides with the main scale. Mass of the cube is

2.736

g. Find the density of the cube in appropriate significant figures.

The side of a cube is measured by a vernier calliper (10 divisions of a vernier scale coincide with 9 divisions of the main scale, where 1 division of the main scale is 1 mm). The main scale reads 10 mm and the first division of vernier scale coincides with the main scale. Mass of the cube is 2.736 g. Find the density of the cube inappropriate significant figures.

Q. The diameter of the spherical bob is measured using a vernier callipers.