The edge of unit cell of FCC Xe crystal is 620 pm- The radius of Xe atom isA- 219-25 pmB- 235-16 pmC- 189-37 pmD- 209-87 pm

The correct option is A 219.25 pmr=a/2√(2)=620/2√(2)=219.25 pm ...

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Relation between Coefficient and Indices of x and y

The edge of u...

Question

The edge of unit cell of FCC Xe crystal is 620pm. The radius of Xe atom is

219.25 pm

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235.16 pm

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189.37 pm

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209.87 pm

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