The effect of repulsion between the two lone pairs of electrons present on oxygen in water molecule is a:
A
no Change in H−O−H bond angle
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B
decrease in H−O−H bond angle
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C
increase in H−−O−H bond angle
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D
all atoms will be in one plane
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Solution
The correct option is C decrease in H−O−H bond angle In water molecule, if there are no lone pairs on oxygen molecule, it will be linear, but due to lp-lp repulsions, O−H bonds will bend down. Thus, H−O−H bond angle decreases.