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Question

The effect of repulsion between the two lone pairs of electrons present on oxygen in water molecule is a:

A
no Change in HOH bond angle
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B
decrease in HOH bond angle
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C
increase in HOH bond angle
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D
all atoms will be in one plane
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Solution

The correct option is C decrease in HOH bond angle
In water molecule, if there are no lone pairs on oxygen molecule, it will be linear, but due to lp-lp repulsions, OH bonds will bend down. Thus, HOH bond angle decreases.
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