The effective atomic number of $C o (C O)_{4}$ is 35 and hence, is less stable. It attains stability by:

Oxidation of Co.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Reduction of Co.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Dimerization

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Tetramerization.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Dimerization
The effective atomic number of $C o (C O)_{4}$ is 35 and hence, is less stable. It attains stability by dimerization. In dimer, each $C o (C O)_{4}$ unit shares one electron. So, the EAN of each unit becomes 36.

Suggest Corrections

Similar questions

Q. An effective atomic number of

C o (C O)_{4}

35

and hence is less stable, It attains stability by :

Q. An effective atomic number of

C o (C O)_{4}

35

and hence is less stable. It attains stability by

Q. The effective atomic number of

C o (C O)_{4}

is 35 and hence is less stable. It attains stability by:

A carbocation is a group of atoms with a positively charged carbon atom having six electrons in the valence shell after sharing. Carbocations are formed in the heterolysis of a bond and are planar species. Stability of carbocation is determined by inductive effect, hyperconjugation and resonance effect. Greater the number of contributing structures more is the stability of a Carbocation. Electron releasing groups (+I effect) increases the stability of a carbocation whereas the electron withdrawing groups (I effect) have an opposite effect.

Which of the following is most stable carbocation?

It is thought that atoms combine with each other such that the outermost orbit acquires a stable configuration of 8 electrons. If stability were attained with 6 electrons rather than with 8, what would be the formula of the stable fluoride ions?

Join BYJU'S Learning Program

The effective atomic number of Co(CO)4 is 35 and hence, is less stable. It attains stability by:

The correct option is C DimerizationThe effective atomic number of Co(CO)4 is 35 and hence, is less stable. It attains stability by dimerization. In dimer, each Co(CO)4 unit shares one electron. So, the EAN of each unit becomes 36.

The effective atomic number of $C o (C O)_{4}$ is 35 and hence, is less stable. It attains stability by:

The correct option is C Dimerization
The effective atomic number of $C o (C O)_{4}$ is 35 and hence, is less stable. It attains stability by dimerization. In dimer, each $C o (C O)_{4}$ unit shares one electron. So, the EAN of each unit becomes 36.