The effective atomic number of Cr (atomic no. 24) in $[C r (N H_{3})_{6}] C l_{3}$ is

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Solution

The correct option is C 33
$C r^{+ 3} (N H_{3})_{6}] C l_{3} E A N = 24 + 2 \times 6 - 3 = 33$

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Similar questions

C r

= 24

[C r (N H_{3})_{6}] C l_{3}

C r

[C r (N H_{3})_{6}]

C l_{3}

= 24

[C r (N H_{3})_{6}] C l_{3}

The effective atomic number $(E A N)$ of $_{24} C r$ in $[C r (N H_{3})_{6}] C l_{3}$ is :

The effective atomic number of central Cu (At. No. 29) metal in $[C u (N H_{3})_{4}] S O_{4}$ is

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