The effective atomic number of Hg(At. No. 80) in the complex $K_{2} [H g I_{4}]$ is

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Solution

The correct option is A 86
The complex ion is $[H g I_{4}]^{2 -}$ and the metal ion is $H g^{2 +}$
$∴$ E.A.N = 80 - 2 + 4(2) = 86.

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