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Question

The effective capacitance between P and Q of the figure below is :

C1=C3=C4=C5=10μF

C2=100μF


9471.JPG

A
10μF
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B
40μF
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C
5μF
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D
20μF
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Solution

The correct option is A 10μF
Equivalent wheat stone bridge capacitors circuit for given circuit is shown in the fig.
In given circuit,
C1C3=1010=1 and C4C5=1010=1
C1C3=C4C5
By wheat stone bridge principle there will be no p.d. across C2 of 100μF hence we can remove C2.
Effective capacitance between P and Q is given by,
CPQ=C1C4C1+C4+C3C5C3+C5

CPQ=10010+10+10010+10=5+5=10μF


775737_9471_ans_7a5e9f31c4404cfe98117a73fb7a584c.jpg

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