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Standard XII
Physics
Lens Maker's Formula
The effective...
Question
The effective focal length of Huygens eyepiece is 3cm. The focal power of field lens is
A
6D
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B
16.7D
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C
3D
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D
10D
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Solution
The correct option is
B
16.7D
Effective focal length,
F
=
3
c
m
For Huygens eyepiece, if focal length of field lens is f, then effective focal length
F
=
f
2
=>
f
=
2
F
=
6
c
m
=
0.06
m
Focal power of field lens =
1
f
=
16.7
D
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