The effective power for a base band signal of wavelength ? is P. Then, the wavelength of the base band signal is doubled.
The new effective power of the signal will become

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Solution

Dear student,
$T h e e f f e c t i v e p o w e r f o r a b a s e b a n d s i g n a l P = \frac{l}{λ^{2}}, w h e r e l i s t h e l e n g t h o f t h e a n t e n n a T h u s P o w e r i s i n v e r s e l y p r o p o r t i o n a l t o w a v e l e n g t h I t w a v e l e n g t h i s d o u b l e d P' = \frac{l}{(2 λ)^{2}} = \frac{l}{4 λ^{2}} o r P' = \frac{P}{4}$

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The effective power for a base band signal of wavelength ? is P. Then, the wavelength of the base band signal is doubled. The new effective power of the signal will become

Dear student, The effective power for a base band signalP=lλ2, where l is the length of the antennaThus Power is inversely proportional to wavelengthIt wavelength is doubledP' =l(2λ)2=l4λ2or P' = P4 Regards

The effective power for a base band signal of wavelength ? is P. Then, the wavelength of the base band signal is doubled.
The new effective power of the signal will become