The effective stress friction angle of a saturated- cohensionless soil is 38- The ratio of shear stress to normal effective stress on the failure plane is

Effective stress friction angle, ϕ ' = 38^∘ Soil is cohesionless so nbsp; C' = 0 From Mohr coulomb nbsp;failure criteria τ ' = C' + σ 'tanϕ ' τ 'σ '= ...

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Soil Mechanics

Mohr Coulomb Failure Criterion-III

The effective...

Question

The effective stress friction angle of a saturated, cohensionless soil is $38^{\circ}$ . The ratio of shear stress to normal effective stress on the failure plane is

0.781

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0.616

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0.488

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0.438

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Solution

The correct option is A 0.781
Effective stress friction angle,

$ϕ^{'} = 38^{\circ}$

Soil is cohesionless so

C' = 0

From Mohr- coulomb failure criteria

$τ^{'} = C^{'} + σ^{'} t a n ϕ^{'}$

$\frac{τ^{'}}{σ^{'}} = t a n ϕ^{'}$

$= t a n 38^{\circ}$

= 0.781

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The effective stress friction angle of a saturated, cohensionless soil is 38∘. The ratio of shear stress to normal effective stress on the failure plane is

The correct option is A 0.781Effective stress friction angle, ϕ′=38∘ Soil is cohesionless so C' = 0 From Mohr- coulomb failure criteria τ′=C′+σ′tanϕ′ τ′σ′=tanϕ′ =tan 38∘ = 0.781

The effective stress friction angle of a saturated, cohensionless soil is $38^{\circ}$ . The ratio of shear stress to normal effective stress on the failure plane is

The correct option is A 0.781
Effective stress friction angle,

$ϕ^{'} = 38^{\circ}$

Soil is cohesionless so

C' = 0

From Mohr- coulomb failure criteria

$τ^{'} = C^{'} + σ^{'} t a n ϕ^{'}$

$\frac{τ^{'}}{σ^{'}} = t a n ϕ^{'}$

$= t a n 38^{\circ}$

= 0.781