Question

The efficiency of a Carnot engine operating with reservoir temperature at $100°C$ and $7°C$ will be?

Answer 1

Step 1: Given

The temperature of the source, $T_1=100°C=(100+273)K=373K$

The temperature of the sink, $T_2=7°C=(7+273)K=280K$

Step 2: Formula used:

Carnot's engine efficiency relation: $\eta =\frac{T_1-T_2}{T_1}$

Step 3: Calculating the Carnot's engine efficiency:

Using Carnot's engine efficiency relation:

$\eta =\frac{T_1-T_2}{T_1}=\frac{373-280}{373}=\frac{93}{373}=$$0.249$

Hence, the efficiency of a Carnot engine is $0.249$.