The efficiency of a Carnot engine operating with reservoir temperature of $100^{o} C$ and $- 23^{o}$ will be :

\frac{100 - 23}{373}

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\frac{100 + 23}{373}

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\frac{100 + 23}{100}

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\frac{100 - 23}{100}

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Solution

The correct option is B $\frac{100 + 23}{373}$
Using the relation for efficiency of Carnot's engine
$η = \frac{T_{1} - T_{2}}{T_{1}} = \frac{373 - 250}{373}$
$= \frac{123}{373} = \frac{100 + 23}{373}$

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