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Standard XII

Chemistry

Carnot Cycle

The efficienc...

Question

The efficiency of a Carnot engine which operates between the two temperatures $T_{1} = 500 K a n d T_{2} = 300 K$ is:

$75 %$

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$50 %$

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$40 %$

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$25 %$

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Solution

The correct option is C
$40 %$

$η = [1 - \frac{T_{2}}{T_{1}}] \times 100 = [1 - \frac{300}{500}] \times 100 = 40 %$

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The efficiency of a Carnot engine which operates between the two temperatures T1=500 K and T2 =300K is:

The correct option is C 40% η=[1−T2T1]×100=[1−300500]×100=40%

The efficiency of a Carnot engine which operates between the two temperatures $T_{1} = 500 K a n d T_{2} = 300 K$ is:

The correct option is C
$40 %$

$η = [1 - \frac{T_{2}}{T_{1}}] \times 100 = [1 - \frac{300}{500}] \times 100 = 40 %$