The efficiency of a fuel cell is given by

\frac{Δ G}{Δ S}

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\frac{Δ G}{Δ H}

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\frac{Δ S}{Δ G}

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\frac{Δ H}{Δ G}

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Solution

The correct option is B $\frac{Δ G}{Δ H}$
The efficiency of a fuel cell
$(n) = \frac{Δ G}{Δ H}$

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Q. The efficiency of a fuel cell is given by:
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Calculate the efficiency of a fuel cell given the heat of combustion of hydrogen is -286.0 kJ Mol^-1 , and the Gibbs free energy change for the fuel cell is -238 kJ mol^-1

Theoretical efficiency of fuel cell is :

What is the efficiency of Fuel cell?

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The efficiency of a fuel cell is given by

The correct option is B ΔGΔHThe efficiency of a fuel cell (n)=ΔGΔH

The correct option is B $\frac{Δ G}{Δ H}$
The efficiency of a fuel cell
$(n) = \frac{Δ G}{Δ H}$