Question

The efficiency of a heat engine if the temperature of the source is ${100}^{\circ }C$ and sink is ${27}^{\circ }C$ is nearly

• A. 0.1
• B. 0.2
• C. 0.3
• D. 0.4

Answer 1

Answer: (B)

0.2

Given: Initial temperature= ${100}^{0}C$ =373K

Final temperature=${27}^{0}C$ =300K

Solution: The heat engine efficiency is given by,

$\eta =1-\frac{T_2}{T_1}$

Substituting the values we get,

$\eta =1-\frac{300}{373}$

On solving we get,

$\eta =0.195\approx 0.2$

Hence, the correct option is (B).