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Question

The efficiency of carnot engine is 50% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60%, then required temperature of the sink will be:

A
100 K
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B
600 K
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C
400 K
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D
500 K
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Solution

The correct option is C 400 K
Given that
Efficiency (η1)=50% & Sink temperature (T2)=500 K and η2=60% & T2=?
From formula, efficiency (η) of carnot cycle
η=(1T2T1)×100%
50100=1500T1
T1=1000 K ...........(1)
for η2=60%
60100=1T21000T2=400 K
Hence, option (c) is the correct answer.

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