The correct option is C −1,−3
Eigen values of X are −2,−3
Eigen values of I are 1, 1
Eigen values of X+I are (−2+1)&(−3+2) i.e, −1,−2
⇒ Eigen values of (X+I)−1 are −1,−12
Given (X+I)−1(X+5I)=(X+I)−1(X+I+4I)
=(X+1)−1(X+1)+4(X+1)−1
=I+4(X+I)−1
∴ The eigen values of
I+4(X+I)−1=1+4(−1)&1+4(−12)
=−3 & −1