The eigen values of the following matrix are ⎡⎢⎣−135−3−16003⎤⎥⎦
A
3,3+5j,6−j
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B
−6+5j,3+j,3−j
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C
3+j,3−j,5+j
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D
3,−1+3j,−1−3j
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Solution
The correct option is D3,−1+3j,−1−3j Characteristic equation is |A−λI|=0 ⇒∣∣
∣∣−1−λ35−3−1−λ6003−λ∣∣
∣∣=0 λ3−λ2+4λ−30=0 (λ−3)(λ2+2λ+10)=0 λ=3,−1±3j
Hence eigen values are 3,−1+3j,−1−3j