No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−1 and 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0 and 5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Cannot be determined
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C0 and 5 A=[4−2−21] |A−λI|=0 ⇒[4−λ−2−21−λ]=0 (4−λ)(1−λ)−4=0 4−5λ+λ2−4=0 λ=0,5
Not: Here, sum of eigen values = trace (A) is satisfied by (a) & (c). Hence we have to solve the characteristic equatuon