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Question

The eigen values of the matrix [4221] are

A
1 and 4
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B
1 and 2
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C
0 and 5
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D
Cannot be determined
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Solution

The correct option is C 0 and 5
A=[4221]
|AλI|=0
[4λ221λ]=0
(4λ)(1λ)4=0
45λ+λ24=0
λ=0,5
Not: Here, sum of eigen values = trace (A) is satisfied by (a) & (c). Hence we have to solve the characteristic equatuon

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