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Question

# The ejection of a photoelectron from a metal in the photoelectric effect experiment can by stopped by applying 0.35 eV when a radiation of 256.7 nm is used. The work function of the metal is:

A
4 eV
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B
5.5 eV
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C
4.5 eV
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D
5 eV
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Solution

## The correct option is C 4.5 eVEnergy of the incident radiation= Work function + Kinetic energy of photoelectron Energy of incident radiation, (E)=hν=hcλ =(6.626×10−34 J s)(3.0×108 m s−1)256.7×10−9 m =7.74×10−19 J =4.83 eV (∵1 eV=1.602×10−19 J) The potential applied gives kinetic energy to the electron. Hence, kinetic energy of the electron = 0.35 eV. ∴Work function=4.83 eV−0.35 eV=4.48 eV

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