The electric component of an electromagnetic wave in SI units are given by Ex-102 sin - 9 - 1014 t-3 - 106z- Ey-0-Ez-0 find the inensity of this radiation-

The correct option is C 13.3 Wm^ 2 Intensity is given by, I = cϵ_∘E_rms Now, for sinusoidal wave, #160; E_rms = E_∘√(2) #160;Given: E_∘ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Dimensional Analysis

The electric ...

Question

The electric component of an electromagnetic wave (in SI units) are given by
$E_{x} = 10^{2} s i n [π (9 \times 10^{14} t - 3 \times 10^{6} z)]$
$E_{y} = 0, E_{z} = 0$ find the inensity of this radiation.

13.3 W m^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.133 W m^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.33 W m^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13.3 \times 10^{- 12} W m^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $13.3 W m^{- 2}$
Intensity is given by, $I = c ϵ_{\circ} E_{r m s}$

Now, for sinusoidal wave,
$E_{r m s} = \frac{E_{\circ}}{\sqrt{2}}$

Given: $E_{\circ} = 10^{2}$

$∴ I = 3 \times 10^{8} \times 8.85 \times 10^{- 12} \times \frac{10^{4}}{2} = 13.3$ $W / m^{2}$

Suggest Corrections

Similar questions

Q. The electric field part of an electromagnetic wave in a medium is represented by

E x = 0, E y = 0,

E_{Z} = 2.5 ((2 π \times 10^{6}) t - (π \times 10^{- 2}) x]

The wave is

Q. The electric field part of an electromagnetic wave in a medium is represented by

E_{x} = 0,

E_{y} = (2.5 \frac{N}{C}) cos [(2 π \times 10^{6} rad/s) t - (π \times 10^{- 2} rad/m) x],

E_{z} = 0

.
The wave is :

Q. Choose the correct answer from the alternatives given. The electric field part of an electromagnetic wave in a medium is represented

E_{x} = 0,

E_{y} = 2.5 \frac{N}{C} c o s [(2 π \times 10^{6} \frac{r a d}{m}) t - (π \times 10^{- 2} \frac{r a d}{s}) x], E_{z} = 0.

The wave is

Q. The electric field part of an electromagnetic wave in a medium is represented by

E_{x} = 0; E_{y} = 2.5 {NC}^{- 1} cos [(2 π \times 10^{6} {rad s}^{- 1}) t - (π \times 10^{- 2} {rad m}^{- 1}) x]; E_{z} = 0.

Then, the waves is

An electromagnetic wave travelling through a transparent medium is given by $E_{x} (y, t) = E_{o x} s i n 2 π [\frac{y}{5 \times 10^{- 7}} - 4 \times 10^{14} t]$ in SI units. Then what is the refractive index of the medium?

Join BYJU'S Learning Program

The electric component of an electromagnetic wave (in SI units) are given byEx=102sin[π(9×1014t−3×106z)]Ey=0,Ez=0 find the inensity of this radiation.

The correct option is C 13.3Wm−2Intensity is given by, I=cϵ∘ErmsNow, for sinusoidal wave, Erms=E∘√2 Given: E∘=102∴I=3×108×8.85×10−12×1042=13.3 W/m2

The electric component of an electromagnetic wave (in SI units) are given by
$E_{x} = 10^{2} s i n [π (9 \times 10^{14} t - 3 \times 10^{6} z)]$
$E_{y} = 0, E_{z} = 0$ find the inensity of this radiation.

The correct option is C $13.3 W m^{- 2}$
Intensity is given by, $I = c ϵ_{\circ} E_{r m s}$

Now, for sinusoidal wave,
$E_{r m s} = \frac{E_{\circ}}{\sqrt{2}}$

Given: $E_{\circ} = 10^{2}$

$∴ I = 3 \times 10^{8} \times 8.85 \times 10^{- 12} \times \frac{10^{4}}{2} = 13.3$ $W / m^{2}$