Question

The electric current in a circuit from $+2A$ to $-2A$ in a tinu interval of ${10}^{-2}$. another coll of resistance $20\Omega$ and inductance $2\pi$ is placed near. find the induced current in the second will.

Answer 1

using Faraday's law
The magnitude of emf induced $\epsilon =l\frac{△I}{△t}$
so the current in the coil $=\frac{\epsilon }{R}=\frac{L}{R}\frac{△I}{△t}$
$△I=2-(-2)=4A,△t={10}^{-2}s,L=2H$ and $R=20\Omega$
$I_{induced}=\frac{2}{20}\times \frac{4}{{10}^{-2}}=40A$