The electric current in a discharging $R - C$ circuit $3$ given by $i = t_{o} e^{- + / R C}$ where $i_{o}, R$ and $C$ are constant parameters and $t$ is time let $i_{o} = 2.00 A, R = 6.00 \times 10^{5} Ω, C = 0.500 μ F$ .
Find approximately the current at $0.31 s$ .

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Solution

$ι$ = $ι_{0}$ $e^{\frac{t}{R c}}$

at
t = 0.31

$ι = 2 e^{\frac{- 0.3}{0.3}}$

$ι = \frac{5.8}{3} e$ Ampere

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The electric current in a discharging R-C circuit is given by $i = i_{o} e^{\frac{- t}{R C}}$ where $i_{o}$ , R and C are constant parameters and $t$ is time. Let $i_{o}$ = 2.00 A, R= $6 \times 10^{5}$ Ω and C = 0.500 $μ$ F.

(a) Find the current at t = 0.3 s.

(b) Find the rate of change of current at t = 0.3 s

Q. The electric current in a charging

R - C

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i = i_{o} e^{- t / R C}

where

i_{o}

R

and

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are constant parameters of the circuit and t is time. Find the rate of change of current at (a)

t = 0

, (b)

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, (c)

t = 10 R C

The electric current in a charging R-C circuit is given by $i = i_{o} e^{\frac{- t}{R C}}$ where io, R and C are constant parameter of the circuit and t is time. Find the rate of change of current at (x)t=0, (y)t=RC, (z)t=10 RC

$(i) \frac{- i_{o}}{R C} (i i) 0 (i i i) \frac{- i_{o}}{R C_{e}} (i v) \frac{- i_{o}}{R C_{e}^{10}} (v) \frac{- i_{o} e^{10}}{R C}$

Q. The electric current in a charging R−C circuit is given by i = i₀e^−t^/RC where i₀, R and C are constant parameters of the circuit and t is time. Find the rate of change of current at (a) t = 0, (b) t = RC, (c) t = 10 RC.

The electric current in a charging R-C circuit is given is given by $i = i_{o} e^{\frac{- t}{R C}}$ where io, R and C are constant parameter of the circuit and t is time. Find the rate of change of current at (x)t=0, (y)t=RC, (z)t=10 RC

$(i) \frac{- i_{o}}{R C} (i i) 0 (i i i) \frac{- i_{o}}{R C_{e}} (i v) \frac{- i_{o}}{R C_{e}^{10}} (v) \frac{- i_{o} e^{10}}{R C}$

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The electric current in a discharging R−C circuit 3 given by i=toe−+/RC where io,R and C are constant parameters and t is time let io=2.00A,R=6.00×105Ω,C=0.500 μF.Find approximately the current at 0.31 s.

ι = ι0 etRcat t = 0.31 ι=2e−0.30.3 ι=5.83e Ampere

The electric current in a discharging $R - C$ circuit $3$ given by $i = t_{o} e^{- + / R C}$ where $i_{o}, R$ and $C$ are constant parameters and $t$ is time let $i_{o} = 2.00 A, R = 6.00 \times 10^{5} Ω, C = 0.500 μ F$ .
Find approximately the current at $0.31 s$ .

$ι$ = $ι_{0}$ $e^{\frac{t}{R c}}$

at
t = 0.31

$ι = 2 e^{\frac{- 0.3}{0.3}}$

$ι = \frac{5.8}{3} e$ Ampere