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Question

The electric current in an X-ray tube operating at 40 kV is 5 mA . If efficiency is 1%. Find
(a) power emitted as X-ray.
(b) power converted to heat.

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Solution

The operating power, $P = V I = (40 \times 10^{3}) (5 \times 10^{- 3}) = 200 W$
As efficiency 1 % so power emitted as X-ray is $P_{X - r a y} = P \times \frac{1}{100} = 2 W$
Power converted to heat is $P_{h e a t} = P - P_{X - r a y} = 200 - 2 = 198 W$

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