The electric field $0.50 m$ from a small sphere with a positive charge of $7.2 \times 10^{5} C$ is

2.6 \times 10^{6} N / C

[inward]

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2.9 \times 10^{- 4} N / C

[inward]

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2.6 \times 10^{6} N / C

[outward]

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2.9 \times 10^{- 4} N / C

[outward]

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Solution

The correct option is C $2.6 \times 10^{6} N / C$ [outward]
$E = \frac{K q}{r^{2}}$

$⟹ E = \frac{9 \times 10^{9} \times 7.2 \times 10^{5}}{(0.5)^{2}}$

$⟹ E = 2.6 \times 10^{16} N / C$
The direction of field is outward, since the charge is positive.

Answer-(C)

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The electric field 0.50m from a small sphere with a positive charge of 7.2×105C is

The correct option is C 2.6×106N/C [outward]E=Kqr2⟹E=9×109×7.2×105(0.5)2⟹E=2.6×1016N/C The direction of field is outward, since the charge is positive.Answer-(C)

The electric field $0.50 m$ from a small sphere with a positive charge of $7.2 \times 10^{5} C$ is

The correct option is C $2.6 \times 10^{6} N / C$ [outward]
$E = \frac{K q}{r^{2}}$

$⟹ E = \frac{9 \times 10^{9} \times 7.2 \times 10^{5}}{(0.5)^{2}}$

$⟹ E = 2.6 \times 10^{16} N / C$
The direction of field is outward, since the charge is positive.

Answer-(C)