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Question

The electric field associated with an e.m. wave in vacuum is given by E=40cos(kz6×108t)^i, where E,z and t in volt/m, meter and seconds respectively. The value of wave vector k is

A
6m1
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B
3m1
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C
2m1
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D
0.5m1
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Solution

The correct option is C 2m1
Given: The electric field associated with an electromagnetic wave in vacuum is given by E=40cos(kz6×108t)^i , where E, z and t are in volt per meter, meter and second respectively.
To find the value of wave vector k
Solution:
We know electromagnetic wave eqution is
E=E0cos(kzωt)
And given equation is
E=40cos(kz6×108t)^i
By comparing these two, we get
ω=6×108 and
E0=40^i
we also know,
Speed of electromagnetic wave, v=ωk
where v is the speed of the light
Hence, k=ωvk=6×1083×108k=2m1
is the required value

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