Question

The electric field components in the given figure are $E_x=\alpha x^{\frac{1}{2}},E_y=E_z=0$ in which $\alpha =800N{C}^{-1}{m}^{\frac{–1}{2}}$. The charge within the cube is if net flux through the cube is $1.05N{m}^2{C}^{-1}$ (assume a = 0.1 m)

• A. $9.27\times {10}^{-12}C$
• B. $9.27\times {10}^{12}C$
• C. $6.97\times {10}^{-12}C$
• D. $6.97\times {10}^{12}C$

Answer 1

The correct option is A

$9.27\times {10}^{-12}C$

By Gauss’s law,

$\varphi =\frac{q}{{ϵ}_0}$

or $q=\varphi {ϵ}_0$

$=1.05\times 8.854\times {10}^{-12}C=9.27\times {10}^{-12}C$