The electric field due to a point charge at a distance 1 m from it is 900 N/C. The magnitude of the charge is

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A point charge produces an electric field of magnitude $5.0 {NC}^{- 1}$ at a distance of 40 cm from it. What is the magnitude of charge?

The electric field due to a charge at a distance of $3 m$ from it is $500 N / C$ . The magnitude of the charge is $[\frac{1}{4 π ε_{0}} = 9 \times 10^{9} N m^{2} / C^{2}]$ :

Q. A point charge q produces an electric field of magnitude

2 N C^{- 1}

at a point distance

0.25 m

from it. Find the value of charge.

At a point due to a point charge, the values of electric field intensity and potential are 32 N $C^{- 1}$ and 16 J $C^{- 1}$ ,respectively. Calculate the

a. magnitude of the charge,and

b. distance of the charge from the point of observation.

The electric field due to a charge at a distance of 3 m from it is 500 N/coulomb. The magnitude of the charge is $[\frac{1}{4 π ϵ_{0}} = 9 \times 10^{9} \frac{N - m^{2}}{c o u l o m b^{2}}]$

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