The electric field in a region is given by E - Ax2- - By - - Cz2 k-The SI units of A-B and C are- respectively-

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Standard XII

Physics

EMF and EMF Devices

The electric ...

Question

The electric field in a region is given by $E = \frac{A}{x^{2}}^i + B y^j + C z^{2}^k$
The $S I$ units of $A, B$ and $C$ are, respectively.

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Solution

Units of $\frac{A}{x^{2}} = B y = C z^{2}$ is equal to unit of electric field.
the unit of electric field is $N / C$
So the SI unit of $A$ is
$= N m^{2} / C$
The SI unit of $B$ is
$= N / m C$
The SI unit of $C$ is

$= N / m^{2} C$

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The electric field in a region is given by E=Ax2^i+By^j+Cz2^kThe SI units of A,B and C are, respectively.

Units of Ax2=By=Cz2 is equal to unit of electric field.the unit of electric field is N/CSo the SI unit of A is=Nm2/CThe SI unit of B is=N/mCThe SI unit of C is =N/m2C

The electric field in a region is given by $E = \frac{A}{x^{2}}^i + B y^j + C z^{2}^k$
The $S I$ units of $A, B$ and $C$ are, respectively.

Units of $\frac{A}{x^{2}} = B y = C z^{2}$ is equal to unit of electric field.
the unit of electric field is $N / C$
So the SI unit of $A$ is
$= N m^{2} / C$
The SI unit of $B$ is
$= N / m C$
The SI unit of $C$ is

$= N / m^{2} C$