The electric field in a region of space is given by →E=(^5i+^2j)Nc−1. The electric flux due to this field through an area 2m2lying in the Y-Z plane in S.I. units is
A
10
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B
20
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C
10√2
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D
2√29
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Solution
The correct option is B10 As 2m2 area is in y-z plane its area vector which is perpendicular to y-z plane is in x axis. ∴ area vector =2(^i) given E=5i+2j We know flux ϕ=E.A =(2i).(5i+2j) ϕ=10