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Question

The electric field in a region surrounding the origin is uniform and along x− axis. A small circle is drawn with the centre at origin and cutting the axes at points A, B, C and D having coordinates (a,0), (0,a), (−a,0) and (0,−a) respectively. Then the potential energy for a test charge q placed at these position will be minimum at:

A
A
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B
B
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C
C
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D
D
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Solution

The correct option is A A The points A, B, C and D have been shown in the above figure. The dotted lines are equally spaced equipotential surfaces. ⇒ The points B and D are situated on the diameter of the circle, which is an equipotential surface. ∴VB=VD Also, potential decreases in the direction of electric field →E. ⇒VC>VB=VD>VA And P.E for a charge is U=qV Hence, Umin will be for position A, because V is minimum at A.

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