The electric field in an electromagnetic wave is given by E - 50sin-2 pi- lambda-ct - x- N-C- Calculate the energy contained in a cylinder of cross-section 10cm-2 and length 50 cm along the axis-

Dear student, energy density is given by 12 #949; #160;E2 nbsp; nbsp; nbsp; nbsp; nbsp; uE=12 isin;oE2 multiply by volume to this and get to ...

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Question

The electric field in an electromagnetic wave is given by E = 50sin((2π/λ)(ct - x)) N/C. Calculate the energy contained in a cylinder of cross-section 10cm^2 and length 50 cm along the axis.

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E = (50 N C^{- 1}) sin ω (t - \frac{x}{c})

c m^{2}

c m

10 {c m}^{2}

50 c m

E = 50 sin ω (t - x / C)

E = (50 N C^{- 1}) sin ω (t - \frac{x}{c})

c m^{2}

c m

z -

E_{x} = E_{\circ} sin (k z - ω t)

E = E_{0} sin (ω t - k x)

E

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