The correct option is C from n-side to p-side
After joining p-type and n-type semiconductors, electrons from the n-region near the p-n interface tend to diffuse into the p region. As electrons diffuse, they leave positively charged ions (donors) in the n region. Likewise, holes from the p-type region near the p-n interface begin to diffuse into the n-type region, leaving fixed ions (acceptors) with negative charge. Hence, the regions nearby the p-n interfaces lose their neutrality and become charged, with positive charge on n-side and negative charge on p-type. Thus, the electric field in the depletion layer of an unbiased p-n junction is from n-side to p-side.