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Intermolecular Forces

The electric ...

Question

The electric field intensity at a point near and outside the surface of a charged conductor of any shape is ' $E_{1}$ '. The electric field intensity due to uniformly charged infinite thin plane sheet is ' $E_{2}$ '. The relation between ' $E_{1}$ ' and ' $E_{2}$ ' is :

2 E_{1} = E_{2}

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E_{1} = E_{2}

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E_{1} = 2 E_{2}

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E_{1} = 4 E_{2}

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Solution

The correct option is C $E_{1} = 2 E_{2}$
Electric field outside the conductor $E_{1} = \frac{σ}{ϵ_{o}}$
Electric field due to uniformly charged infinitely thin plate $E_{2} = \frac{σ}{2 ϵ_{o}}$
$⟹$ $E_{1} = 2 E_{2}$

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