The electric field intensity $E,$ current density $J$ and specific resistance $k$ are related to each other through the relation

E = \frac{J}{k}

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E = J k

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E = \frac{k}{J}

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k = J E

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Solution

The correct option is B $E = J k$
We know that $J = \frac{I}{A}$ and $E = \frac{I}{σ A}$ ;
$∴ E = \frac{J}{σ} = ρ J = k J$ .
hence correct option is option B.

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