The electric field intensity vector of a plane wave propagating in lossless medium is given byE-2cos108t-z-x-2sin108t-z-y VmThe polarization of the wave is

Wave is travelling in + z direction and E_x leads E_y component by 90^∘. Also |E_x|=|E_y|. Therefore Left circular. ...

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Circular Polarization

The electric ...

Question

The electric field intensity vector of a plane wave propagating in lossless medium is given by
$\to E = 2 cos (10^{8} t - z) {^a}_{x} + 2 sin (10^{8} t - z) {^a}_{y} \frac{V}{m}$
The polarization of the wave is

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\to E = E_{0} e^{- 0.4 π z} cos (2 π \times 10^{5} t - 0.4 π z)_{x} V / m

\to H (x . t) = 10 s i n (50000 t + 0.004 x + 30) {^a}_{y}

{^a}_{y}

1 (μ_{r 1} = 1, \in_{r 1} = 4)

2 (μ_{r 2} = 1, \in_{r 2} = 9)

ϵ = ϵ_{0}, μ = μ_{0} a n d σ = 1.5 \times 10^{- 5} S / m

\to E = 8 e^{a z} sin (10^{6} π t - β z) {^a}_{y}, V / m

σ = 0

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