Question

The electric field just outside the surface of conductor of area $A$ and surface charge density $\sigma$ is given by

• A. $\frac{\sigma }{3{ϵ}_0}$
• B. $\frac{\sigma }{2{ϵ}_0}$
• C. $\frac{\sigma }{{ϵ}_0}$
• D. $\frac{2\sigma }{{ϵ}_0}$

Answer 1

The correct option is C $\frac{\sigma }{{ϵ}_0}$

Conductor of area $=A$

Surface charge density $=6$

The field just outside the conductor $=$ Surface is given by $E=\frac{\sigma }{{ϵ}_0}$

Where $\sigma =$ Surface charge density

${ϵ}_0=$ permittivity of space.