The electric field near to the surface of the charged conductor

is directed at

45^{o}

to the surface and depends upon charge density.

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is directed parallel to the surface and independent of charge density.

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directed along normal to surface and depends upon charge density

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directed along normal to surface and independent of charge density.

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Solution

The correct option is C directed along normal to surface and depends upon charge density
Electric field is perpendicular to surface of charge conductor and its value is $\to E = \frac{σ}{ε_{0}} ˆ n$

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Similar questions

Q. The electric field intensity near to surface of charged conductor
A. Is directed along the surface
B. is directed normal to the surface
C. depends upon local radius of curve
D. depends upon surface charge density at the point

Q. Charge density on the surface of a conducting solid depends upon:

Q. Two conducting spheres of radii

r_{1}

and

r_{2}

are charged to the same surface charge density. The ratio of electric fields near their surface is :

A hollow charged conductor has a tiny hole cut into its surface. Show that the electric field in the hole is , where is the unit vector in the outward normal direction, and is the surface charge density near the hole.

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The electric field near to the surface of the charged conductor

The correct option is C directed along normal to surface and depends upon charge densityElectric field is perpendicular to surface of charge conductor and its value is →E=σε0ˆn

The correct option is C directed along normal to surface and depends upon charge density
Electric field is perpendicular to surface of charge conductor and its value is $\to E = \frac{σ}{ε_{0}} ˆ n$