The electric field of a plane electromagnetic were travelling in the +ve Z-direction is described by:

E_{x} = E_{0} s i n (k z + c o t)

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E_{x} = E_{0} s i n (k z - c o t)

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E_{x} = E_{0} s i n (2 k z)

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E_{x} = E_{0} s i n (k z)

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Solution

The correct option is B $E_{x} = E_{0} s i n (k z - c o t)$
For the electric field of a plane electromagnetic wave to be travelling in the +ve Z-direction, the argument of the cosine function should be $k z - ω t$ . Therefore the required electric field of a plane electromagnetic wave is given by:
$E_{x} = E_{0} s i n (k z - ω t)$

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Similar questions

\to E = E_{0} sin (k z - ω t)^i

\to B = B_{0} sin (k z - ω t)^j

\to E = E_{0} sin (k z - ω t) (^i +^j) .

sin (k z - ω t)

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E_{x} = E_{\circ} sin (k z - ω t)

t = 0

\to E (x, y) = 10^j cos [(6 x + 8 z)]

\to B (x, z, t)

c

E x = 0, E y = 0,

E_{Z} = 2.5 ((2 π \times 10^{6}) t - (π \times 10^{- 2}) x]

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