The electric field of an electromagnetic wave propagating in the positive z-direction is given by

$E =_{x} s i n (ω t - β z) +_{y} s i n (ω t - β z + π / 2)$ . The
wave is

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Solution

Ans : (c)

Equal amplitudes and out of phase by $90^{\circ}$ , wave is circularly polarized. Tracing the time advancing E on the z = 0 plane at t = 0, t = T/4, t = T/2 gives left/right notations.

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\to H

\to H =^x \frac{5 \sqrt{3}}{η_{0}} c o s (ω t - β z) +^y \frac{5}{η_{0}} s i n (ω t - β z + \frac{π}{2})

\to E = 10 ({^a}_{y} + j {^a}_{z}) e^{- j 25 x}

\to E = 5 cos (ω t + β z) {^a}_{x} - 5 sin (ω t + β z + 180^{\circ}) {^a}_{y} A / m

\to E = (2 {^a}_{x} + j {^a}_{y}) e^{- (β z - j ω t)} V / m

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