The electric field of an electromagnetic wave traveling through a vacuum is given by equation $E = E_{0} s i n (k x - t)$ . The quantity that is independent of wavelength is?

k

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\frac{k}{ω}

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k^{2}

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k^{3}

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Solution

The correct option is B $\frac{k}{ω}$
$E = E_{0} s i n (k x - t)$

From above equation wave lenght:
$λ = \frac{2 π}{K}$

$\frac{V}{ω} = \frac{2 π}{K}$

$\frac{K}{ω} = \frac{2 π}{V} =$ Constant

Option B

Suggest Corrections

Similar questions

E = E_{0} s i n (K x - ω t) .

E = E_{0} sin (k x - ω t)

\to E = 40 cos (k z - 6 \times 10^{8} t)^i

k

E = E_{0} sin (k x - ω t)

B = B_{0} sin (k x - ω t)

E = E_{0} sin (k x - ω t)

B = B_{0} sin (k x - ω t)

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