Question

The electric field on two sides of charged thin sheet is shown in figure. The charge density on sheet is

• A. Zero
• B. $16{ϵ}_0$
• C. $18{ϵ}_0$
• D. $2{ϵ}_0$

Answer 1

The correct option is D $2{ϵ}_0$

$\varphi =E_{2}A-E_{1}A$
$=\frac{q}{{ϵ}_0}=\frac{\sigma A}{{ϵ}_0}$
$E_2-E_1=\frac{\sigma }{{ϵ}_0}$
$\sigma =(E_2-E_1){ϵ}_0$
$=18-16=2{ϵ}_0$