the electric field part of an emw in vacuum is given by E=6cos (1.2y +3.6 810^8 t) i cap , then find 1.direction of propagation 2.expression for magnetic field part of the wave . HOW TO FIND DIRECTION OF MAGNETIC FIELD ?

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Suppose that the electric field part of an electromagnetic wave in vacuum is E = {(3.1 N/C) cos [(1.8 rad/m) y + (5.4 × 10⁶ rad/s)t]} .

(a) What is the direction of propagation?

(b) What is the wavelength λ?

(d) What is the amplitude of the magnetic field part of the wave?

(e) Write an expression for the magnetic field part of the wave.

Q. The electric field of a plane electromagnetic wave propagating along the

x - direction

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\to E = E_{0}^j cos (ω t - k x) .

The magnetic field

\to B,

at the moment

t = 0

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. electric field and magnetic field are parallel to each other.

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. electric field and magnetic field both are perpendicular to direction of propagation of wave.

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. What is the direction of the magnetic field at time t = 0 and position x = 0 ?

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