MyQuestionIcon

6

You visited us 6 times! Enjoying our articles? Unlock Full Access!

Conventional current

The electric ...

Question

The electric field strength at a distance $r$ from a charge $q$ is $E$ . What will be electric field strength if the distance of the observation point is increased to $2 r$ ?

A

E / 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

E / 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

E / 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $E / 4$
As new distance $= 2 r$ and electric field due to single charge, $E \propto \frac{1}{r^{2}}$ , therefore, new intensity $= E / 4$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. The electric field strength due to ring of radius R at a distance x from its centre on the axis of ring carrying charge Q is given by

E = \frac{1}{4 π ε_{0}} \frac{Q x}{(R^{2} + x^{2})^{3 / 2}}

. At what distance from the centre will the electric field be maximum?

Q. Two point charges Q and -2Q are placed at some distance apart. If the electric field at the location of Q is E, then the electric field at the location of -2Q will be

Q. A proton of mass

m

e

is released from rest in a uniform electric field of strength

E

. The time taken by it to travel a distance

d

in the field is :

Q. An electron of charge

e

at rest is accelerated in a uniform electric field of strength

E

K E

attained by it as it travels through a distance

S

Q. The intensity of electric field E due to charge Q at distance r.

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Benjamin Franklin 1

PHYSICS

Watch in App

explore_more_icon

Explore more

Conventional current

Standard X Physics

Join BYJU'S Learning Program

CrossIcon