Question

The electric field $\overrightarrow{E}$ is constant in both magnitude and direction. Consider a path of length $d$ at an angle $\theta ={60}^o$ with respect to field line shown in the figure. The potential difference between points 1 and 2 is :

• A. $\frac{E}{d\cos {60}^o}$
• B. $Ed\cos {60}^o$
• C. $\frac{Ed}{\cos {60}^o}$
• D. $\frac{E}{d}\cos {60}^o$

Answer 1

The correct option is B $Ed\cos {60}^o$

The value of potential difference $=E.d$

Since, the Cos component is there then

or, $V=Ed\cos \theta$

or, $V=Ed\cos {60}^0$ [$\because$ $\theta ={60}^0$]