Question

The electric field within the nucleus is generally observed to be linearly dependent on $r$. This implies.

• A. $a=0$
• B. $a=\frac{R}{2}$
• C. $a=R$
• D. $a=\frac{2R}{3}$

Answer 1

The correct option is C $a=R$

$\oint \overrightarrow{E}.\overrightarrow{ds}=\frac{ze}{{\epsilon }_0}E.4\pi a^2=\frac{ze}{{\epsilon }_0}$

Inside and at surface to be equal,

$E=\frac{ze}{4\pi a^2{\epsilon }_0}=\frac{ze}{4\pi R^2{\epsilon }_0}$

E should be linear for solid sphere also,

$a=R$